Question
A square is inscribed in the circle x^{2} + y^{2} – 2x + 4y + 3 = 0. Its sides are parallel to the coordinates axes. Then one vertex of the square is

None of these



easy
Solution
None of these
The centre of the given circle is (1, –2). Since the sides of the square inscribed in the circle are parallel to the coordinates axes, so the x coordinates of any vertex cannot be equal to 1 and its y coordinate cannot be equal to –2.
Hence none of the point given in (a), (b) or (c) can be the vertex of the square. Thus the correct answer is none of these.
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